跳到正文
← 返回论文列表与筛选
阅读说明

本页整理公开书目信息,不生成学术质量评分。AI 解读根据题名及所注明的摘要或原文片段生成,未完成全文核验,可能有误;具体假设、证明与结论请核对原文。摘要保留来源文本,未经模型改写。

DOI 首次登记不等于接收或发表日期。部分更正、评论等条目没有独立摘要;缺少可靠材料时保留待补状态。

本页为预印本版本;arXiv 收录、作者填写的期刊信息以及作者既有发表经历,都不单独证明本篇已接收。作者发表记录按 OpenAlex 身份与完整姓名、本站覆盖期刊 ISSN 及正式卷期核对,只展示已核实例,档案仍可能误合并。

引用量采用 OpenAlex 单条关联记录,不合计多个记录;关联记录可能包含正式发表版本,不等于此版本单独引用。缺失不视为零,引用指标不代表论文质量。

关注作者按书目中的完整姓名匹配,同名和姓名变体需人工辨别。相关论文先按共享细分方向和具体方法排列,再参考通用方法与发表日期。

分类依据与纠错

AI 根据所提供的论文材料归类:摘要研究通用半参数单调指数模型的计算与渐近性质,未明确结果类型或对应的经济学细分应用。

反馈分类问题

正在核对关联版本…

代码、数据与补充材料

正在核对对应版本的资源…

关注这篇论文的作者
Qingsong Yao

超大样本半参数单调指数模型的随机学习

研究问题
当样本量极大、全样本半参数估计计算负担过重时,能否利用小批量随机更新加速单调指数模型估计,并保留渐近精度?
方法与思路
作者反复抽取小规模子样本,以损失函数梯度更新参数,并用子样本的Nadaraya–Watson核估计替代非参数部分,最终平均迭代估计。
材料陈述的贡献
摘要称,适当选择子样本规模和核函数可大幅提速;迭代平均与全样本估计之差在根号n尺度可忽略,并具一致性和渐近正态性。
阅读关注点
应核对子样本规模、带宽、步长和迭代次数的联合条件,以及所谓任意初值与全样本渐近等价结论的具体适用范围。
阅读边界
这是arXiv预印本,同行评审或接收状态未核实;摘要未列出算法条件和实际运行时间,约n倍提速是有条件的作者陈述。

原文摘要

I study the estimation of semiparametric monotone index models in the scenario where the number of observation points $n$ is extremely large and conventional approaches fail to work due to heavy computational burdens. Motivated by the mini-batch gradient descent algorithm (MBGD) that is widely used as a stochastic optimization tool in the machine learning field, I proposes a novel subsample- and iteration-based estimation procedure. In particular, starting from any initial guess of the true parameter, I progressively update the parameter using a sequence of subsamples randomly drawn from the data set whose sample size is much smaller than $n$. The update is based on the gradient of some well-chosen loss function, where the nonparametric component is replaced with its Nadaraya-Watson kernel estimator based on subsamples. My proposed algorithm essentially generalizes MBGD algorithm to the semiparametric setup. Compared with full-sample-based method, the new method reduces the computational time by roughly $n$ times if the subsample size and the kernel function are chosen properly, so can be easily applied when the sample size $n$ is large. Moreover, I show that if I further conduct averages across the estimators produced during iterations, the difference between the average estimator and full-sample-based estimator will be $1/\sqrt{n}$-trivial. Consequently, the average estimator is $1/\sqrt{n}$-consistent and asymptotically normally distributed. In other words, the new estimator substantially improves the computational speed, while at the same time maintains the estimation accuracy.

笔记与分组
相关领域论文