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本页整理公开书目信息,不生成学术质量评分。AI 解读根据题名及所注明的摘要或原文片段生成,未完成全文核验,可能有误;具体假设、证明与结论请核对原文。摘要保留来源文本,未经模型改写。

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分类依据与纠错

AI 根据所提供的论文材料归类:摘要研究通用回归中的模型选择与平均理论,未明确给出所列细分方向的专门模型或应用。

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代码、数据与补充材料

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关注这篇论文的作者
Jingfu Peng
Yuhong Yang

模型平均能否改进模型选择?

研究问题
在嵌套回归模型中,即使模型平均没有降低近似误差的优势,它是否仍能显著改进模型选择或最优候选模型?
方法与思路
作者在嵌套模型框架中比较模型选择与凸权重模型平均的估计损失或风险,推导理论结论并用模拟支持。
材料陈述的贡献
摘要称在一定条件下,模型平均可显著改进不可知的最优候选模型,说明模型选择的渐近效率并非最优性能保证。
阅读关注点
应核对嵌套结构、损失与风险定义、显著改进的量级,以及所需条件如何区别于通过抵消模型偏差获得的优势。
阅读边界
仅依据所给出版社摘要;改进成立的具体条件和幅度未说明,不能推出模型平均在所有候选集合中都优于选择。

原文摘要

In regression, model averaging (MA) provides an alternative to model selection (MS), and asymptotic efficiency theories have been derived for both MS and MA. Basically, under sensible conditions, MS asymptotically achieves the smallest estimation loss/risk among the candidate models, and MA does so among averaged estimators from the models with convex weights. Clearly, MA can beat MS by any extent in rate of convergence when all the candidate models have large biases that can be canceled out by a MA scheme. To our knowledge, however, a foundational issue has not been addressed in the literature. That is, when there is no advantage of reducing approximation error, does MA offer any significant improvement over MS in regression estimation? In this paper, we answer this question in a nested model setting that has been often used in the frequentist MA research area. A remarkable implication is that the much celebrated asymptotic efficiency of MS (e.g., by AIC) does not necessarily justify MS as commonly interpreted as achieving the best possible performance. In a nutshell, the oracle model (i.e., the unknowable best model among all the candidates) can be significantly improved by MA under certain conditions. A simulation study supports the theoretical findings.

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